Saturday, October 11, 2014

Problem For The Day! - 11 - Oct - 2014


Let X1,X2 and X3 be three i.i.d. exponential distributed random variables with parameter λ=1. Let Y1=X1+X2, Y2=X1+X3 and Y3=X2+X3. The probability that {Y1>Y2>Y3} is

(A) 12 (B) 13 (C) 16 (D) 56

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