Bhupala
Saturday, October 11, 2014
Problem For The Day! - 11 - Oct - 2014
Let
X
1
,
X
2
and
X
3
be three i.i.d. exponential distributed random variables with parameter
λ
=
1
. Let
Y
1
=
X
1
+
X
2
,
Y
2
=
X
1
+
X
3
and
Y
3
=
X
2
+
X
3
. The probability that
{
Y
1
>
Y
2
>
Y
3
}
is
(A)
1
2
(B)
1
3
(C)
1
6
(D)
5
6
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